Javascript list members of groups

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Customer

Javascript list members of groups

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Hi,

I have following code to list members of Alfresco groups:

var siteGroups = new Object(); 
var logFile = space.childByNamePath("GroupAndUsers.txt");

if (logFile == null)
{
logFile = space.createFile("GroupAndUsers.txt");
}

// return all results, skip 0
var paging = utils.createPaging(-1, 0);

siteGroups = groups.getGroups(null, paging);

for (var i=0; i<siteGroups.length; i++)
{
if (siteGroups[i].displayName.indexOf("gl_aa_alfresco_") == -1 &&
siteGroups[i].displayName.indexOf("gl_center_") == -1 &&
siteGroups[i].displayName.indexOf("site_") == -1)
{

logFile.content += siteGroups[i].displayName + "\n";

var group = people.getGroup(siteGroups[i].id);
var members = people.getMembers(group,false);

for (var member in members)
{
logFile.content += member.properties.userName + "\n";
}
}
}

logFile.save();
logFile.content; 12345678910111213141516171819202122232425262728293031323334

But line

  var members = people.getMembers(group,false);

gives an error. What is wrong?

Using Alfresco 5.0.3.

Thanks,

Patrick

1 Solution

Accepted Solutions
Highlighted
Professional

Re: Javascript list members of groups

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The error is that the group you are passing is not defined. This is because when you call people.getGroup you are passing in siteGroups[i].id but there is no "id" property of a SiteGroup object.

Instead, try passing in siteGroups[i].fullName, see ScriptGroup object | Alfresco Documentation 

View solution in original post

6 Replies
Highlighted
Customer

Re: Javascript list members of groups

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Error message is:

2019-01-28 14:09:18,134 ERROR [org.springframework.extensions.webscripts.AbstractRuntime] [http-apr-8080-exec-45] Exception from executeScript - redirecting to status template error: 002815346 Failed to execute script 'workspace://SpacesStore/7eb39344-f918-40e8-8d96-ddaa60be2b09': Group is a mandatory parameter
org.alfresco.scripts.ScriptException: 002815346 Failed to execute script 'workspace://SpacesStore/7eb39344-f918-40e8-8d96-ddaa60be2b09': Group is a mandatory parameter

Highlighted
Professional

Re: Javascript list members of groups

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The error is that the group you are passing is not defined. This is because when you call people.getGroup you are passing in siteGroups[i].id but there is no "id" property of a SiteGroup object.

Instead, try passing in siteGroups[i].fullName, see ScriptGroup object | Alfresco Documentation 

View solution in original post

Highlighted
Customer

Re: Javascript list members of groups

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Thanks Jeff, that works. But one more question concerning getting the users per group. I have code

		var group = people.getGroup(siteGroups[i].fullName); 
var members = people.getMembers(group,false);

for (var member in members)
{
var memberNode = people.getPerson(member.userName);

if (memberNode != null)
{

logFile.content += " - " + memberNode.properties["lastName"] + ";" + memberNode.properties["firstName"] + ";" + memberNode.properties["email"] + "\n";
}
}

but I do not get any users listed in logFile... so I must do something wrong there too...

Any help much appreciated!

Highlighted
Established Member II

Re: Javascript list members of groups

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Hello,

With code line  "for (var member in members)"  what you are really doing is an iteration through indexes of the array members .

So to access each individual member object you need to write members[member] inside the loop.

Your code  should be somethig like:

var group = people.getGroup(siteGroups[i].fullName); 
var members = people.getMembers(group,false);

for (var member in members)
{
var memberNode = people.getPerson(members[member].properties["userName"]);
if (memberNode != null)
{
logger.log(" - " + memberNode.properties["lastName"] + ";" + memberNode.properties["firstName"] + ";" + memberNode.properties["email"]);
}
}‍‍‍‍‍‍‍‍‍‍‍‍‍

Regards

Highlighted
Customer

Re: Javascript list members of groups

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It should just be

for (var j=0; j<members.length; j++) 
{
logFile.content += " - " + members[j].properties.lastName + ";" + members[j].properties.firstName + ";" + members[j].properties.email + "\n";
}
Highlighted
Established Member II

Re: Javascript list members of groups

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Yes, with a little refactoring this is a more accurate solution.

Regards